Optimal. Leaf size=231 \[ -\frac {2 (d \cot (e+f x))^{5/2}}{5 d^2 f}+\frac {2 \sqrt {d \cot (e+f x)}}{f}+\frac {\sqrt {d} \log \left (\sqrt {d} \cot (e+f x)-\sqrt {2} \sqrt {d \cot (e+f x)}+\sqrt {d}\right )}{2 \sqrt {2} f}-\frac {\sqrt {d} \log \left (\sqrt {d} \cot (e+f x)+\sqrt {2} \sqrt {d \cot (e+f x)}+\sqrt {d}\right )}{2 \sqrt {2} f}+\frac {\sqrt {d} \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt {d \cot (e+f x)}}{\sqrt {d}}\right )}{\sqrt {2} f}-\frac {\sqrt {d} \tan ^{-1}\left (\frac {\sqrt {2} \sqrt {d \cot (e+f x)}}{\sqrt {d}}+1\right )}{\sqrt {2} f} \]
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Rubi [A] time = 0.20, antiderivative size = 231, normalized size of antiderivative = 1.00, number of steps used = 14, number of rules used = 10, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.476, Rules used = {16, 3473, 3476, 329, 211, 1165, 628, 1162, 617, 204} \[ -\frac {2 (d \cot (e+f x))^{5/2}}{5 d^2 f}+\frac {2 \sqrt {d \cot (e+f x)}}{f}+\frac {\sqrt {d} \log \left (\sqrt {d} \cot (e+f x)-\sqrt {2} \sqrt {d \cot (e+f x)}+\sqrt {d}\right )}{2 \sqrt {2} f}-\frac {\sqrt {d} \log \left (\sqrt {d} \cot (e+f x)+\sqrt {2} \sqrt {d \cot (e+f x)}+\sqrt {d}\right )}{2 \sqrt {2} f}+\frac {\sqrt {d} \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt {d \cot (e+f x)}}{\sqrt {d}}\right )}{\sqrt {2} f}-\frac {\sqrt {d} \tan ^{-1}\left (\frac {\sqrt {2} \sqrt {d \cot (e+f x)}}{\sqrt {d}}+1\right )}{\sqrt {2} f} \]
Antiderivative was successfully verified.
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Rule 16
Rule 204
Rule 211
Rule 329
Rule 617
Rule 628
Rule 1162
Rule 1165
Rule 3473
Rule 3476
Rubi steps
\begin {align*} \int \cot ^3(e+f x) \sqrt {d \cot (e+f x)} \, dx &=\frac {\int (d \cot (e+f x))^{7/2} \, dx}{d^3}\\ &=-\frac {2 (d \cot (e+f x))^{5/2}}{5 d^2 f}-\frac {\int (d \cot (e+f x))^{3/2} \, dx}{d}\\ &=\frac {2 \sqrt {d \cot (e+f x)}}{f}-\frac {2 (d \cot (e+f x))^{5/2}}{5 d^2 f}+d \int \frac {1}{\sqrt {d \cot (e+f x)}} \, dx\\ &=\frac {2 \sqrt {d \cot (e+f x)}}{f}-\frac {2 (d \cot (e+f x))^{5/2}}{5 d^2 f}-\frac {d^2 \operatorname {Subst}\left (\int \frac {1}{\sqrt {x} \left (d^2+x^2\right )} \, dx,x,d \cot (e+f x)\right )}{f}\\ &=\frac {2 \sqrt {d \cot (e+f x)}}{f}-\frac {2 (d \cot (e+f x))^{5/2}}{5 d^2 f}-\frac {\left (2 d^2\right ) \operatorname {Subst}\left (\int \frac {1}{d^2+x^4} \, dx,x,\sqrt {d \cot (e+f x)}\right )}{f}\\ &=\frac {2 \sqrt {d \cot (e+f x)}}{f}-\frac {2 (d \cot (e+f x))^{5/2}}{5 d^2 f}-\frac {d \operatorname {Subst}\left (\int \frac {d-x^2}{d^2+x^4} \, dx,x,\sqrt {d \cot (e+f x)}\right )}{f}-\frac {d \operatorname {Subst}\left (\int \frac {d+x^2}{d^2+x^4} \, dx,x,\sqrt {d \cot (e+f x)}\right )}{f}\\ &=\frac {2 \sqrt {d \cot (e+f x)}}{f}-\frac {2 (d \cot (e+f x))^{5/2}}{5 d^2 f}+\frac {\sqrt {d} \operatorname {Subst}\left (\int \frac {\sqrt {2} \sqrt {d}+2 x}{-d-\sqrt {2} \sqrt {d} x-x^2} \, dx,x,\sqrt {d \cot (e+f x)}\right )}{2 \sqrt {2} f}+\frac {\sqrt {d} \operatorname {Subst}\left (\int \frac {\sqrt {2} \sqrt {d}-2 x}{-d+\sqrt {2} \sqrt {d} x-x^2} \, dx,x,\sqrt {d \cot (e+f x)}\right )}{2 \sqrt {2} f}-\frac {d \operatorname {Subst}\left (\int \frac {1}{d-\sqrt {2} \sqrt {d} x+x^2} \, dx,x,\sqrt {d \cot (e+f x)}\right )}{2 f}-\frac {d \operatorname {Subst}\left (\int \frac {1}{d+\sqrt {2} \sqrt {d} x+x^2} \, dx,x,\sqrt {d \cot (e+f x)}\right )}{2 f}\\ &=\frac {2 \sqrt {d \cot (e+f x)}}{f}-\frac {2 (d \cot (e+f x))^{5/2}}{5 d^2 f}+\frac {\sqrt {d} \log \left (\sqrt {d}+\sqrt {d} \cot (e+f x)-\sqrt {2} \sqrt {d \cot (e+f x)}\right )}{2 \sqrt {2} f}-\frac {\sqrt {d} \log \left (\sqrt {d}+\sqrt {d} \cot (e+f x)+\sqrt {2} \sqrt {d \cot (e+f x)}\right )}{2 \sqrt {2} f}-\frac {\sqrt {d} \operatorname {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\frac {\sqrt {2} \sqrt {d \cot (e+f x)}}{\sqrt {d}}\right )}{\sqrt {2} f}+\frac {\sqrt {d} \operatorname {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\frac {\sqrt {2} \sqrt {d \cot (e+f x)}}{\sqrt {d}}\right )}{\sqrt {2} f}\\ &=\frac {\sqrt {d} \tan ^{-1}\left (1-\frac {\sqrt {2} \sqrt {d \cot (e+f x)}}{\sqrt {d}}\right )}{\sqrt {2} f}-\frac {\sqrt {d} \tan ^{-1}\left (1+\frac {\sqrt {2} \sqrt {d \cot (e+f x)}}{\sqrt {d}}\right )}{\sqrt {2} f}+\frac {2 \sqrt {d \cot (e+f x)}}{f}-\frac {2 (d \cot (e+f x))^{5/2}}{5 d^2 f}+\frac {\sqrt {d} \log \left (\sqrt {d}+\sqrt {d} \cot (e+f x)-\sqrt {2} \sqrt {d \cot (e+f x)}\right )}{2 \sqrt {2} f}-\frac {\sqrt {d} \log \left (\sqrt {d}+\sqrt {d} \cot (e+f x)+\sqrt {2} \sqrt {d \cot (e+f x)}\right )}{2 \sqrt {2} f}\\ \end {align*}
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Mathematica [A] time = 0.45, size = 172, normalized size = 0.74 \[ \frac {\sqrt {d \cot (e+f x)} \left (-8 \cot ^{\frac {5}{2}}(e+f x)+40 \sqrt {\cot (e+f x)}+5 \sqrt {2} \log \left (\cot (e+f x)-\sqrt {2} \sqrt {\cot (e+f x)}+1\right )-5 \sqrt {2} \log \left (\cot (e+f x)+\sqrt {2} \sqrt {\cot (e+f x)}+1\right )+10 \sqrt {2} \tan ^{-1}\left (1-\sqrt {2} \sqrt {\cot (e+f x)}\right )-10 \sqrt {2} \tan ^{-1}\left (\sqrt {2} \sqrt {\cot (e+f x)}+1\right )\right )}{20 f \sqrt {\cot (e+f x)}} \]
Antiderivative was successfully verified.
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fricas [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: TypeError} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \sqrt {d \cot \left (f x + e\right )} \cot \left (f x + e\right )^{3}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.18, size = 190, normalized size = 0.82 \[ -\frac {2 \left (d \cot \left (f x +e \right )\right )^{\frac {5}{2}}}{5 d^{2} f}+\frac {2 \sqrt {d \cot \left (f x +e \right )}}{f}-\frac {\left (d^{2}\right )^{\frac {1}{4}} \sqrt {2}\, \arctan \left (\frac {\sqrt {2}\, \sqrt {d \cot \left (f x +e \right )}}{\left (d^{2}\right )^{\frac {1}{4}}}+1\right )}{2 f}+\frac {\left (d^{2}\right )^{\frac {1}{4}} \sqrt {2}\, \arctan \left (-\frac {\sqrt {2}\, \sqrt {d \cot \left (f x +e \right )}}{\left (d^{2}\right )^{\frac {1}{4}}}+1\right )}{2 f}-\frac {\left (d^{2}\right )^{\frac {1}{4}} \sqrt {2}\, \ln \left (\frac {d \cot \left (f x +e \right )+\left (d^{2}\right )^{\frac {1}{4}} \sqrt {d \cot \left (f x +e \right )}\, \sqrt {2}+\sqrt {d^{2}}}{d \cot \left (f x +e \right )-\left (d^{2}\right )^{\frac {1}{4}} \sqrt {d \cot \left (f x +e \right )}\, \sqrt {2}+\sqrt {d^{2}}}\right )}{4 f} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.56, size = 199, normalized size = 0.86 \[ -\frac {10 \, \sqrt {2} d^{\frac {5}{2}} \arctan \left (\frac {\sqrt {2} {\left (\sqrt {2} \sqrt {d} + 2 \, \sqrt {\frac {d}{\tan \left (f x + e\right )}}\right )}}{2 \, \sqrt {d}}\right ) + 10 \, \sqrt {2} d^{\frac {5}{2}} \arctan \left (-\frac {\sqrt {2} {\left (\sqrt {2} \sqrt {d} - 2 \, \sqrt {\frac {d}{\tan \left (f x + e\right )}}\right )}}{2 \, \sqrt {d}}\right ) + 5 \, \sqrt {2} d^{\frac {5}{2}} \log \left (\sqrt {2} \sqrt {d} \sqrt {\frac {d}{\tan \left (f x + e\right )}} + d + \frac {d}{\tan \left (f x + e\right )}\right ) - 5 \, \sqrt {2} d^{\frac {5}{2}} \log \left (-\sqrt {2} \sqrt {d} \sqrt {\frac {d}{\tan \left (f x + e\right )}} + d + \frac {d}{\tan \left (f x + e\right )}\right ) - 40 \, d^{2} \sqrt {\frac {d}{\tan \left (f x + e\right )}} + 8 \, \left (\frac {d}{\tan \left (f x + e\right )}\right )^{\frac {5}{2}}}{20 \, d^{2} f} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 2.87, size = 90, normalized size = 0.39 \[ \frac {2\,\sqrt {d\,\mathrm {cot}\left (e+f\,x\right )}}{f}-\frac {2\,{\left (d\,\mathrm {cot}\left (e+f\,x\right )\right )}^{5/2}}{5\,d^2\,f}+\frac {{\left (-1\right )}^{1/4}\,\sqrt {d}\,\mathrm {atan}\left (\frac {{\left (-1\right )}^{1/4}\,\sqrt {d\,\mathrm {cot}\left (e+f\,x\right )}}{\sqrt {d}}\right )\,1{}\mathrm {i}}{f}+\frac {{\left (-1\right )}^{1/4}\,\sqrt {d}\,\mathrm {atan}\left (\frac {{\left (-1\right )}^{1/4}\,\sqrt {d\,\mathrm {cot}\left (e+f\,x\right )}\,1{}\mathrm {i}}{\sqrt {d}}\right )}{f} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \sqrt {d \cot {\left (e + f x \right )}} \cot ^{3}{\left (e + f x \right )}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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